# 5-1 classified ads

Published on: August 5 2023 by pipiads

Ken is a mechanic who owns Ace Auto Repair. He is in need of a foreign car expert and is placing a 12-line classified ad. The cost of the ad, x lines long, can be determined using a piecewise function.

In our text, x represents the number of lines in the classified ad. Let's break down each piece of the function to understand its meaning.

- For x ≤ 4, the cost is $56. This means that a classified ad with four lines or less will cost $56.

- For x > 4, the cost is $56 + 6(x - 4). This means that for each additional line above four, there is an additional cost of $6.

To find the cost of a twelve line ad, we need to use the second piece of the function since 12 is greater than 4. So, we have c(12) = $56 + 6(12 - 4). Solving this equation, we get a cost of $104 for Ken to place a 12-line ad in the paper.

Now let's move on to example four. An online job search site charges employers fees to post job listings. The price per posting decreases as the number of postings increases, encouraging employers to add more postings.

The question asks for the percent savings if an employer decides to post four jobs instead of one. To find the percent discount, we can use the formula:

Percent discount = (Original price - Discount price) / Original price

The original price is the cost of posting one job, and the discount price is the cost of posting four jobs. Looking at the table, we find the price per posting for one job is $395, and for four jobs, it is $350.

Plugging these values into the formula, we have (395 - 350) / 395. Solving this equation, we get approximately 0.113, which is equal to 11.3%. This tells us that the employer gets a discount of about 11% by posting four jobs instead of one.

Table of Contents About 5-1 classified ads

## 5 1 Classified ads

# Introduction #

Good morning, fifth-grade girls! I am delighted to start this new school year with all of you. Today's English class is all about entertainment advertisements, specifically classified ads. Let's dive right into it!

# Asking about Prices #

- How much do these jeans cost? (referring to a pair of James Jamon Chartis jeans)

- What are those pants made of? (referring to denim jeans)

- The answer is: They cost 200 to 250 pesos.

# Writing the Response #

- The answer to the first question is: Hard hundreds in ti pesos.

- The answer to the second question is: T hunter city's 200 to 250 pesos.

# Additional Examples #

- How much is this skateboard? (showing a picture)

- The answer is: It is forty-six pesos.

- How much are these books? (showing a stack of books)

- The answer is: Six hundred pesos.

- How much is the house? (referring to a picture)

- The answer is: Eight hundred and ninety thousand pesos.

# Conclusion #

That wraps up our first class. Make sure to practice asking and answering questions about prices. You can find more resources online for numbers from 1 to 100, as well as hundreds. I've sent an exercise to your WhatsApp, which you can complete and paste into your notebooks or write down if you can't print it. If you have any questions, feel free to search for answers online or ask me in the next class. See you next time!

## Financial Algebra 5.1 Classified Ads

Alright guys, welcome to Chapter 5, Section 5.1 on classified ads. Let's jump into the vocabulary section.

1. Sales tax: The tax on sales or on the receipts from sales. It is an additional fee added to the price of a product or service.

2. Domain: A set of values that can be inputted into a function. It limits the range of possible values on the x-axis.

3. Piecewise functions: Also known as split functions, these are equations that can be written in a mathematical shorthand. Different equations apply for different situations.

4. Cusp: A point where two lines from a piecewise function meet. It represents a change or shift in direction.

Now let's move on to the checking for understanding section.

Example 1: What is the sales tax on a $35,000 vehicle in California with a 7.5% sales tax rate?

To find the sales tax, we first convert the 7.5% to a decimal (0.075). Then, we multiply it by the price of the vehicle ($35,000) to get an answer of $2,625.

Example 2: Ramon wants to place a 5-line ad in the newspaper for three weeks. The newspaper charges $27 for the first three lines and $11 for each additional line. How much will the ad cost for three weeks?

For the first week, Ramon will be charged $27 for the three lines, and an additional $11 for the two additional lines. So the total cost for week 1 is $49. For the next two weeks, he will be charged the same amount, resulting in a total cost of $147.

Example 3: Create a word problem using a piecewise function.

Let's say there is a house party that costs $36.50 per person. If you go alone, it will cost you $36.50. If you bring two friends, it will still cost $36.50. However, for each additional person, the cost increases by $6.25. So, if you bring three friends, it will be $36.50, but if you bring a fourth friend, it will be $42.75.

Lastly, let's find the cusp of the graph for the following piecewise function.

The graph consists of two lines. The first line has a constant value of $42.50 until x reaches 5. Then, it increases by $7 for each additional value of x. The cusp occurs at the point where the two lines meet, which is at x = 5.

## Kijiji Auto Posting Software 2018 - AUTO POST KIJIJI Secret Reveal

So, hi, hello, and welcome to the posting tool that I'm going to show you today. I'm going to explain how the key Gigi out poster works. Basically, you will get this software from the two person tools icon, which has many modules like Twitter, jutsu, e-commerce, Craigslist, Facebook, back pay, and YouTube. Today, we're going to focus on the key Gigi posting software.

Before we dive into the software, there are a few things you need to do. Firstly, you need to go into the software download and run a file to make sure Internet Explorer 6 renders as Internet Explorer 11. This is important for uploading pictures. You only need to do this once, but if you need to do it again, just follow the same steps.

Now, let's talk about posting. Posting is similar to posting on Craigslist but for Canada and other classified sites. To start posting, you need to make sure the picture upload feature is working. Pictures make ads more convincing, so it's important to check this before you start. In the key Gigi posting section, you'll find a web browser where you can upload pictures. If you don't see the picture after uploading, it means something is wrong, and you need to fix it before you start posting.

Now that we've checked the picture upload feature, let's move on to posting. The first step is to create some ads. On the top, you'll find a tab to extract ads from Craigslist. This will allow you to add ads to your QGG ad management. You can use this to post ads whenever you want. There is also a section where you can spin the text of your ads.

The web browser section is where you'll post and delete ads. You can post ads again after deleting them. The files section is used to generate tags for downloads. You can generate tags for different cities and keywords to extract specific ads. If you already have the necessary information, you can load the folder and select the files you want to use.

For example, let's say you want to post ads about computers. You can select the specific city or select random. Then, click on Get Ads to extract the ads. Each ad will open on Craigslist, and you can use the Use This Ad button to copy the ad information.

To fill out the contact information, go to the second tab and select a profile. If you don't have a profile, you can create one by entering your name, phone number, email, QGG login information, postal code, and website. Once you save the profile, it will be available for future use. You can switch between profiles and login with different accounts. You can also change your proxy if needed.

Now that you have a profile, you can go back to the Craigslist ads section and choose an ad to post. Click on Use This Ad and modify the ad as needed. Change the title, phone number, and add your website if desired. You can also search for an image related to your ad and paste the URL into the software.

And that's it! You're now ready to start posting ads using the key Gigi software. Remember to follow the steps I mentioned earlier to ensure a smooth posting process. Good luck!

## 5 1 Video

Alright, we're now in the first chapter of Unit 5, which is the last unit for the course. So good job getting this far! Today, we're going to talk about classified ads and how to compute the cost of classified ads on used cars. Let's dive in!

In this article, we will discuss how to calculate the cost of classified ads and sales tax on used cars. We will explore different scenarios and use algebraic expressions to find the total cost. So, let's get started!

Example 1:

Cary purchased a used car for $7,400 and had to pay an 8.5% sales tax. How much tax did she pay?

- To find the tax, we need to convert the sales tax percentage into a decimal. So, 8.5% becomes 0.085.

- Then, we multiply the total cost of the car ($7,400) by the decimal value of the sales tax (0.085).

- Using a calculator, we get $629. Please pause and solve this example on your own before continuing.

Example 2:

The sales tax rate in Mary Ann's state is 4%. She purchases a car for X dollars. Express the total cost of the car.

- To find the total cost, we need to calculate the sales tax on the car. We can do this by multiplying the car's price (X) by the decimal value of the sales tax (0.04).

- Then, we add the cost of the car (X) and the tax together.

- So, the algebraic expression for the total cost of the car is X + (X * 0.04). Solve this example on your own before moving forward.

Example 3:

John plans to sell his car and places a five-line ad in the newspaper. The cost of a classified ad is $31 for the first two lines and $6 per extra line. What will John's ad cost to run for two weeks?

- For one week, the cost of the ad is $31 for the first two lines, plus $6 for each additional line.

- So, for two weeks, we simply double the cost of the ad for one week.

- The ad will cost $49 to run for two weeks. Solve this example at your own pace before continuing.

Example 4:

Jason is writing a program to compute ad costs for his company. They charge $40 to $50 for up to five lines, and $7 for each additional line. Express the cost of an ad with X lines as a function algebraically.

- We need to create a piecewise function to represent the cost of the ad.

- The first scenario is when there are up to five lines. In this case, the cost is $42.50.

- The second scenario is when there are more than five lines. The cost is $42.50 plus $7 for each additional line over five.

- So, the algebraic expression for the cost of an ad with X lines is:

- If X ≤ 5: $42.50

- If X > 5: $42.50 + ($7 * (X - 5))

Take a moment to solve this example before moving on.

Example 5:

The Smithtown News charges $38 for a classified ad that is four or fewer lines long. Each line above four lines costs an additional $6. Express the cost of the ad as a piecewise function.

- The cost of the ad is $38 for four or fewer lines.

- For each line above four, there is an additional cost of $6 per line.

- So, the algebraic expression for the cost of the ad is:

- If X ≤ 4: $38

- If X > 4: $38 + ($6 * (X - 4))

Solve this example in your own words before continuing.

Example 6:

Roxanne set up the following piecewise function to represent the cost of an auto classified ad for her hometown newspaper:

Cost of ad (C) =

- $60 for five or fewer lines

- $5 for each line over five

- In words, the cost of the ad is $60 if there are five or fewer lines. For each additional line over five, the cost increases by $5.

- Solve this example by explaining the cost in everyday language before moving on.

In this article, we learned how to compute the cost of classified ads and sales tax on used cars. We used algebraic expressions and piecewise functions to find the total cost based on different scenarios. Remember to apply these concepts in real-life situations. Keep up the good work!

## Lesson 5.1 Express classified ad prices as piecewise functions

In this article, we will be discussing various examples related to piecewise functions and how they can be used to calculate costs in different scenarios.

Example 1: Calculating the Cost of an Ad

Ken, a mechanic who owns Ace Auto Repair, needs to place a 12-line ad on jobsrs.com. The cost of the ad depends on the number of lines. If the number of lines is 4 or less, the cost is $56. If the number of lines is more than 4, Ken will pay $56 plus $6 for each additional line. To calculate the cost of a 12-line ad, we substitute x with 12 in the equation. Thus, the cost of a 12-line ad would be $104.

Example 2: Plumbers' Trade Print Publication

Plumbers' Trade Print Publication charges $13 for each of the first four lines of an ad. After the fourth line, they charge $7.50 for each additional line. To represent this cost using a piecewise function, we can use the variable c to denote the cost. If the number of lines is 4 or less, the cost is always $13. For each additional line after the fourth, the cost is calculated by multiplying the number of additional lines by $7.50. Therefore, the piecewise function for the cost of an x-line ad would be c(x) = $13 if x ≤ 4, and c(x) = $13 + ($7.50 * (x - 4)) if x > 4.

Example 3: Online Job Search Site

An online job search site charges employers x dollars to post a job on their website. They offer a 16% discount if 20 or more jobs are posted. To express the cost of posting 31 jobs algebraically, we use the variable x to represent the original cost. With the 16% discount, the employer is only paying 84% of the original cost. Therefore, the cost of 31 job postings would be 0.84 * x.

Example 4: Job Find Website

Job Find charges employers x dollars to post a job on their website. They offer a 16% discount if 20 or more jobs are posted. To express the cost of posting 31 jobs algebraically, we use the variable x to represent the original cost. Since the employer is posting 31 jobs, they qualify for the 16% discount. Thus, the cost of 31 job postings would be 0.84 * x.

Example 5: Jane's Printing Services

Jane's Printing Services charges $29.95 to print 200 high-quality business cards. Each additional set of 100 cards costs $14. To express the cost of printing x sets of cards as a piecewise function, we use the variable r to represent the cost. For the first two sets, the cost is $29.95. For each additional set after the second, the cost is $14. Therefore, the piecewise function for the cost of x sets of cards would be r(x) = $29.95 if x ≤ 2, and r(x) = $29.95 + ($14 * (x - 2)) if x > 2.

Piecewise functions are a useful tool for calculating costs in various scenarios. By using different equations for different ranges of values, we can accurately determine the cost based on specific conditions. These examples demonstrate how piecewise functions can be applied in different situations, from calculating ad costs to printing services.

## 5-1-1 Deterministic Approach

Music plays a significant role in our lives, bringing joy, relaxation, and inspiration. However, when it comes to the safety of nuclear reactors, music is not the focus. In this article, we will delve into the deterministic approach used to analyze the safety of new clubs (nuclear reactors) and how typical transients and accidents are selected for study. We will also explore the design basis accidents and their categorization according to frequency and consequences. Join us as we take a closer look at the importance of safety in the world of nuclear reactors.

Deterministic Approach and Selection of Transients and Accidents:

In analyzing the safety of new clubs, a deterministic approach is used. This approach involves studying a selection of typical transients and accidents that represent a family of events. Due to the vast number of potential occurrences in a nuclear reactor, it is not feasible to study every detail. Therefore, a careful selection is made to focus on significant events such as pipe ruptures. Three representative sizes of pipe breaks are chosen: complete rupture, small break, and intermediate break. These studies aim to present what would happen in such accidents and are known as design basis accidents.

Considerations in Design Basis Accidents:

Design basis accidents are crucial in designing the safety systems of nuclear reactors. These accidents are studied with conservative assumptions, taking worst-case conditions into account. For instance, all initial parameters are assumed to be at their worst condition, and stringent design criteria for safety systems are applied. Common mode failures and the quality and qualification of equipment are also important considerations in these studies. The objective is to ensure the safety systems can withstand accident environments in terms of temperature and pressure.

Categorization of Design Basis Events:

Design basis events are categorized based on their frequency and consequences. The higher the potential consequences, the lower the frequency should be. These events are classified into internal events, which involve failures within the system or components, and external hazards, which are events that could occur outside but impact the plant. Examples of external hazards include earthquakes, flooding, and plane crashes. By categorizing the events, the design conditions for normal operation, transients, accidents, and severe accidents can be defined.

Frequency and Consequences of Design Conditions:

The frequency of design conditions is linked to their consequences. Normal operation has a higher frequency but must remain within authorized limits for radioactivity release. Transients have a frequency ranging from once a year to once in a century, and their consequences should also remain within authorized limits. Accidents with potential high consequences should have a very low frequency, less than one in a million years. The objective is to ensure the highest potential consequences have the lowest frequency, while the unacceptable domain is avoided.

Design Condition and System Design:

Design conditions serve to define and design various systems within a nuclear reactor. From normal operation to severe accidents, each design condition plays a role in determining system requirements. Main systems, control and regulation, emergency systems, and containment are all designed based on these conditions. The study of severe accidents also helps in emergency preparedness planning and the inclusion of necessary arrangements.

Examples of Design Basis Accidents:

Rupture of primary piping, steam line, and feed water line are examples of design basis accidents. These accidents have an impact on the reactor's reactivity and must be carefully studied. Another example is the ejection of control rods and fuel unloading during reactor shutdown. These accidents involve fuel assembly cooling loss and require thorough analysis.

Complexity of Safety Analysis:

Safety analysis of nuclear reactors involves sophisticated computer codes and 3D modeling of thermal hydraulics. These models simulate complex phenomena such as steam-water equilibrium and flow distribution. They are based on numerous experiments conducted on major equipment components of reactors. The analysis of transients and accidents requires meticulous calculations and modeling to ensure the temperature of fuel remains within authorized limits and prevent cladding oxidation.

Safety is of utmost importance when it comes to nuclear reactors. The deterministic approach and selection of transients and accidents help in understanding and designing the safety systems of these reactors. Design basis accidents, categorized according to frequency and consequences, guide the design of various systems and emergency preparedness plans. With advanced computer codes and modeling, complex safety analysis is conducted to ensure the temperature and integrity of fuel remain within authorized limits. By prioritizing safety, we can continue to harness the power of nuclear energy responsibly.